lentilă planconvexă
R = 10 cm
n = 1,5
β = 10
-
x₁,x₂ = ?
[tex] \beta = \frac{y2}{y1} = \frac{x2}{x1} = 10 \ \textless \ =\ \textgreater \ x2 = 10*x1[/tex]
[tex] \frac{1}{x2} - \frac{1}{x1} = \frac{1}{f} = (n-1)\frac{1}{R} \\ \frac{1}{f} = (1,5 - 1) \frac{1}{10} \\ \frac{1}{f} = \frac{0,5}{10} = 0,05 \ \textless \ =\ \textgreater \ \frac{1}{x2} - \frac{1}{x1} = 0,05[/tex]
[tex]x2 = 10*x1 \\ \frac{1}{10*x1} - \frac{1}{x1} = 0,05\\ \frac{1-10}{10*x1} = 0,05 \\ \frac{-9}{10*x1} =0,05[/tex]
deci -9 = 0,5 * x₁
x₁ = [tex] \frac{-9}{0,5} [/tex]
x₁ = 18 cm
x₂ = x₁ * 10
x₂ = 180 cm
