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Cum rezolv : lim x->2 din x la 2 -4/ xla2-4x-4? Va rog

Răspuns :

[tex] \lim_{x \to 2} \frac{x^2-4}{x^2-4x-4} = \frac{2^2-4}{2^2-4*2-4}= \frac{0}{-8} =0\\ Obs. \lim_{x \to 2,x\ \textgreater \ 2} \frac{x^2-4}{x^2-4x+4} =\lim_{x \to 2,x\ \textgreater \ 2} \frac{(x-2)(x+2)}{(x-2)^2} =\\ =\lim_{x \to 2,x\ \textgreater \ 2} \frac{(x+2)}{(x-2)} =+\infty[/tex]