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\sqrt 1*49+ 1*16 (totul sub radical)
\sqrt 1*25-1*36 (totul sub radical)
rezolvarea o vreau


Răspuns :

[tex]\sqrt{\dfrac{1}{25}-\dfrac{1}{36}}[/tex]

Dupa ce aducem la acelasi numitor si efectuam scaderea fractiilor de sub radical, obtinem:

[tex]\it\sqrt{\dfrac{11}{25\cdot36}}=\dfrac{\sqrt{11}}{5\cdot6}=\dfrac{\sqrt{11}}{30}[/tex]