inecuatia se restrange in [tex] log_{a} 4^{x } \ \textless \ log_{a} 2^{x}+ log_{a} a^{6} [/tex]
[tex] log_{a} 2^{2x} \ \textless \ log_{a} 2^{x} a^{6} [/tex]
daca a>1 obtinem [tex] 2^{2x} \ \textless \ a^{6} 2^{x} , simplificam , cu, 2^{x} obtinem : 2^{x}\ \textless \ a^{6} , logaritmam [/tex] in baza 2 se obtine x<[tex] log_{2} a^{6} [/tex], daca a∈(0,1), logaritmul in baza a este descrescator deci
se obtine[tex] 2^{2x\ \textgreater \ {a^{6} } 2^{x} [/tex] , repetand acelas calcul rezulta x>[tex] log_{2} a^{6} [/tex]
