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multimea solutilor reale ale ecuatiei (2x-5)(x+1)-(x-5)(x+6)=x(x-1)+(3x)°

Răspuns :

(2x-5)(x+1)-(x-5)(x+6)=x(x-1)+(3x)
x24x+25=x2+2x
x24x+25x2=x2+2xx2
4x+25=2x
4x+252x=2x2x
6x+25=0
6x+25−25=0−25
6x=25
6x/−6=−25/6
x=25/6