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1/9·1/7·1/5·1/3(x+2)=-17 ajutatima va rog frumos prin metoda mersului invers ..mersi

Răspuns :

1/9×1/7×1/5×1/3×(x+2)=-17
1/9×1/7×1/5×(x+2)=(-17)×3
1/9×1/7×1/5×(x+2)=-51
1/9×1/7×(x+2)=(-51)×5
1/9×1/7×(x+2)=-255
1/9×(x+2)=(-255)×7
1/9×(x+2)=-1785
x+2=(-1785)×9
x+2=-16065
x=-16065-2
x=-16067


x+2/9x7x5x3=-17
x+2/945=-17
x+2=-17x945
x=-16065-2
x=-16067
sau 
1/7.1/5.1/3(x+2)=-17.9=-153
1/5.1/3(x+2)=-153.7=-1071
1/3(x+2)=-1071.5=-5355
x+2=-5355.3
x+2=-16065
x=-16067