c)
[tex]\arcsin \dfrac{\sqrt3}{2} = \dfrac{\pi}{3}
\\\;\\
arccos\dfrac{\sqrt3}{2}= \dfrac{\pi}{6}
\\\;\\ tg (\dfrac{\pi}{3}-\dfrac{\pi}{6}) =tg \dfrac{\pi}{6} =\dfrac{\sqrt3}{3}[/tex]
a)
[tex]\it2\arcsin x- \pi = 0 \Longrightarrow 2 \arcsin x = \pi \Longrightarrow \arcsin x = \dfrac{\pi}{2}
\\\;\\
\sin(\arcsin x) = \sin \dfrac{\pi}{2} \Longrightarrow x = 1.[/tex]
