NOTEZ SUBSTANTA CaHb;
Scriu ecuatia reactiei de ardere
CaHb + (a+b/4) O2---> aCO2 + b/2 H2O inmultesc cu A moli
Alcatuiesc un sistem de 3 ecuatii
axAx44 =0,3600: .............axA=o,oo81moli
b/2xAx18= 0,1473 b/2xA= 0,0081moli---->a=b/2
(12a+b)xA=0,2455
rezolvi sistemul, cum am inceput eu si afli a si b