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Calculati media aritmetica a numerelor x=3+√2 si y=3-√2

Răspuns :

ma=x+y/2
⇒ma=(3+√2+3-√2)/2=6/2=3
[tex] \frac{3 + \sqrt{2} + 3 - \sqrt{2} }{2} [/tex]
=(3+3)/2=3