ΔABC- triunghi dreptughic
BD si DC- proiectii.
BD= 8 cm
DC=[tex] 5\frac{1}{3} = \frac{16}{3} [/tex]
AD-inaltime
AD=?
AD²=BD*CD
AD²= 8*[tex] \frac{16}{3} [/tex]
AD²=[tex] \frac{128}{3} [/tex]=>AD=[tex] \sqrt{ \frac{128}{3} } \ \textless \ =\ \textgreater \ \frac{ \sqrt{128} }{ \sqrt{3} } = \frac{8 \sqrt{2} }{ \sqrt{3} } rationalizam : \frac{8 \sqrt{6} }{3} [/tex]
