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calculati media ponderata a numerelor 1supra2,2supra3,3supra4cu ponderile 2,3,4

Răspuns :

[tex] \frac{ \frac{1}{2}*2 + \frac{2}{3} *3+ \frac{3}{4} *4}{2+3+4} [/tex]
[tex]   \frac{ 1 + 2 +3}{2+3+4}  [/tex]
6/9
2/3
[tex]m_{a.p.} = \dfrac{\dfrac{1}{2}\cdot2 + \dfrac{2}{3}\cdot3 + \dfrac{3}{4}\cdot4}{2+3+4}=\dfrac{1+2+3}{2+3+4} =\dfrac{\ \ 6^{(3}}{9} = \dfrac{2}{3}.[/tex]