a+b+c=37654 unde a= prima bucata,b=a doua bucate ,c= a treia bucata
a+b=23940
b+c=34562
inlocuim
23940+c=37654,c=37654-23940,c=13714
b=c=34562,b+13714=34562,b=34562-13714,b=20848
a+b=23940,a+20848=23940,a=23940-20848,a=3092
2.
a= primul muncitor
b= al doi=lea
c= al tre-lea
a+b=21630
b+c=21610
c=1790
inlocuim
b+1790=21610,b=21610-1790,b=19820
a+b=21630,a=19820=21630,a=21630-19820,a=1810
atunci a+b+c=?
1810+19820+1790=23420 piese