-transform masa data in nr.moli, stiind M= (40gCa+71gCl)/mol= 111g/mol=
niu= 10x10⁻³g/111g/mol= 0,09x10⁻³=9x10⁻⁵mol
c=niu/V--> C,m= 9x10⁻⁵mol/ 0,2 l= 4,5x10⁻⁴mol/l
-transform masa data in echivalenti gram
n= 10x10⁻³g/111x2g/ Eg= 4,5x10⁻⁵ Eg , unde 2 este valenta calciului
c,n= n/V C= 4,5X10⁻⁵Eg/0,2l= 2,25x10⁻⁴Eg/l