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[tex] 81^{ \frac{1}{4}- \frac{1}{2} log_{9}4 }*49 ^{ log_{7}2 } =[/tex]

Răspuns :

[tex] \frac{ 81^{ \frac{1}{4} } }{81^{ \frac{1}{2} *log _{9}4 }}*7^{2*log_7 2} = \frac{3^ \frac{4}{4} }{9^{log_94}}*7^{log_74}= \frac{3}{4}*4=3 [/tex]