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determinati numarul natural n din egalitatea [0.(6)]la puterea n ÷4 pe3 = 2pe 9....vă rog este urgent!!!

Răspuns :

[0.(6)]^n :4/3 = 2/9
0,(6)=6*9=2/3
(2/3)^n  = 2/9 x4/3
(2/3)^n  = 8/27
(2/3)^n  = 2³/3³
(2/3)^n  = (2/3)³
n=3