[tex] d_{1} [/tex]=40km
[tex] d_{2} =94km[/tex]
Δd=[tex] d_{1}- d_{2} =94km-40km=54km [/tex]
Δt=[tex] \frac{delta.d}{ v_{1}+ v_{2} }= \frac{54km}{162km/h} =0,33 h[/tex]
d=[tex] v_{1} [/tex]×Δt=72km/h×0,33h=24km
[tex] d_{1} +d=40km+24km=64km[/tex]
La borna kilometrica 64
b) Δ[tex] t_{1} [/tex]=[tex] \frac{delta.d}{ v_{2} } = \frac{54km}{90km/h} = 0,6h[/tex]
Δd'=Δ[tex] t_{1} [/tex]×[tex] v_{1} [/tex]=0,6h×72km/h=43,2km
c) Graficul e in poza
