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Rezolvati inecuatia :x+3 supra 7 mai mic sau egal 5 supra ,x apartine multimi N.


Răspuns :

x+3/7 <= 5/x =
x+3/7-5/x <=0

aducem la celasi numitor

x^2+3x-35/7x<=0
x^2+3x-35 = 0
d = 3^2-4*(-35) = 149
x1,2 = -3+/-rad149/2

7x=0 => x= 0 , apartine N