Din cate am inteles din enunt
x=2√3
y=8√3
[tex] \frac{1}{\frac{x-1}{y} }[/tex] = [tex] \frac{y}{x-1} = \frac{8\sqrt{3}}{2\sqrt{3}-1} = \frac{4*2\sqrt{3}}{2\sqrt{3}-1}= \frac{4*2\sqrt{3}*(2\sqrt{3}-1)}{12-1} = \frac{48-8\sqrt{3}}{11}= \frac{8*(6-\sqrt{3})}{11} [/tex]
