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cum rezolv x radical 2 +2x radical 3 - 4x radical 12+ 5x radical 18

Răspuns :

=x√2+2x√3-4x·2√3+5x·3√2
=x√2+2x√3-8x√3+15x√2
=16x√2-6x√3
x√2+2x√3-4x·2√3+5x·3√2 = x√2+2x√3-8x√3+15x√2 = 16x√2-6x√3 = 2x(8√2-3√3)