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4(5x+3)-7=3(4x+5) rezolvati ecuatiile inβ [tex]1,(3)x-1,25=0,8(3)x+0,5[/tex]

Răspuns :

4(5x+3)-7=3(4x+5)
20x+12-7=12x+15
8x=15-5
8x=10
x=10/8
x=5/4

1,(3)x-1,25=0,8(3)x+0,5
1,(3)=1+3/9=1+1/3=4/3
0,8(3)=(83-8)/90=75/90=5/6
1,25=125/100=5/4
0,5=1/2
4x/3-5/4=5x/6+1/2
16x-15=10x+6
6x=21
x=21/6
x=7/2