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Sa se arate că nr. b=(2-radical2)^2 + radical (radical3 +2rad2) ^2+rad( 11-4rad 6)

Răspuns :

b=[tex](2- \sqrt{2})^2+ \sqrt{( \sqrt{3}+2 \sqrt{2})^2}+ \sqrt{11-4 \sqrt{6} }=4-4 \sqrt{2}+2+ \sqrt{3}+2 \sqrt{2}+ \sqrt{(2 \sqrt{2}- \sqrt{3})^2} [/tex]=6-2[tex] \sqrt{2}+ \sqrt{3}+2 \sqrt{2}- \sqrt{3} [/tex]=6