1.
d²=L²+l²+h²=7²=49
L=k/6 L²=k²/36
l=k/9 l²=k²/81
h=h/3 h²=k²/9
k²/36+k²/81+k²/9=49
numitorul comun 324
9k²+4k²+36k²=49*324
49k²=324
k²=324
k=18
L=k/6=18/6=3
l=k/9 =18/9=2
h=h/3=18/3=6
At=2x3x2+2x3x6+2x2x6=12+36+24=72 cm²
2.
tg 30ā°=DD'/DC=DD'/3ā3=1/ā3 DD'=3 cm
At=2x3x3ā3+2x3x4+2x4x3ā3=18ā3+24+24ā3=42ā3+24ā96,75 cm²
distanta
de la [A'(D'AB)] este inaltimea in triunghiul AA'D'
AD'=ā(3²+4²)=ā(9+16)=ā25=5 cm
Atriunghiului=3x4/2=6 cm²
Atriunghiului=5xh/2=6cm² h=2*6/5=2,4 cm
tg([ā”((AB'),(BB'C'))]=3ā3/3=ā3 rezulta
masura [ā”((AB'),(BB'C'))]=60ā°