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Se considera nr.:n= 2^5*13^5-26^5+7^0;m=(3^17:9^8)^2005:27^668. Calculati (m-2n)^1000.

Răspuns :

n= 2^5*13^5-26^5+7^0=2^5*13^5-2^5*13^5+1=1

m=(3^17:9^8)^2005:27^668=(3^17:3^16)^2005:3^2004=3^2005:3^2004=3

(m-2n)^1000=(3-2*1)^1000=1^1000=1