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rezolvati sistemul de ecuatii in metoda reducerii
2x-y=1
6x+2y=0


Răspuns :

2x-y=1| inmultim cu 3
6x+2y=0

=>6x-3y=3
    6x+2y=0

=>-y=3=> y=-3

2x-3=1=>2x=4=>x=2
2x-y=1 |*3
6x+2y=0=>
6x-3y=3
6x+2y=0=>
-y=3=>y=3
2x-3=1
2x=4
x=4:2
x=2