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triunghi ABC dreptunghic AD perpendicular pe BC AD=6 BD=3.6 aflati BC AC AD

Răspuns :

teorema inaltimii
AD=√BD*DC
6=√3,6*DC
36=3,6 *DC
DC=36/3,6=10
BC=3,6+10=13,6
teorema catetei
AB=√3,6*13,6=√48,96=1,2√34≈6,997
CD=√10*13,6=√136=2√34≈11,661