a)11/5×212
cum se procedeaza?
(5×1+1/5)×(2×2+1/2)=6/5×5/2=30/10=3
b)21/4×31/3
(4×2+1/4)×(3×3+1/3)=9/4×10/3=90/12⇒ se simplifica prin3=30/4
c)-55/11×21/5=
-(11×5+5/1)×(5×2+1/5)=-60/11×11/5⇒-60/5⇒-12
d)(-12/3)×(-26/27)=312/81⇒se simplifica prin 3⇔104/27
e)8/15÷51/3=8/15÷(3×5+1/3)=8/15÷16/3=8/15×3/16
=se fac simplificari⇒1/6
-55/6÷(-38/9)=-(35/6)÷(-35/9)=-35/6×(-9/35)=se fac simplificari si ⇒3/2
f)-41/8÷27/16=-(33/8)÷39/16=-33/8×16/39=-66/39=-33/13
g)7/25÷1.4=7/25÷14/10=7/25×10/14=se fac simplificari si⇒2/10=1/10
sucees
