[tex]2,1(3)=2\dfrac{13-1}{90}=2\dfrac{\ 12^{(6}}{90}=2\dfrac{2}{15}=\dfrac{32}{15}[/tex]
Deci, avem:
[tex]a=\dfrac{32}{15}, \ \ \ b = \dfrac{4}{3}
\\\;\\
\dfrac{a}{b}=\dfrac{\dfrac{32}{15}}{\dfrac{4}{3}} =\dfrac{32}{15} : \dfrac{4}{3} = \dfrac{32}{15} \cdot \dfrac{3}{4} =\dfrac{16}{10}=1,6 [/tex]
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