[tex] \frac{a}{b}=2,(6)=2 \frac{6}{9}=2 \frac{2}{3}= \frac{2*3+2}{3}= \frac{8}{3},iar,a= \frac{8}{10}= \frac{4}{5} [/tex]. Din [tex] \frac{a}{b}= \frac{8}{3},avem,b= \frac{3a}{8},inlocuim,pe,a= \frac{4}{5},rezulta,
b= \frac{3* \frac{4}{5} }{8}= \frac{ \frac{12}{5} }{ \frac{8}{1} }= \frac{12}{5}* \frac{1}{8} [/tex]=[tex] \frac{3*4}{5*2*4}= \frac{3}{10}=0,3 [/tex]
