Notam toate triungiurile ABC, AB-cateta1, BC cateta 2, AC ipotenuza, BD-inaltimea
a) Conform teoremei catetei
AB²=AD×AC
AB²=25×49
AB²=1225
AB=√1225
AB=35
deci x=35 cm
b)BC²=CD×AC
9²=CD×10
CD=9² ÷ 10
CD=81 ÷ 10
CD=8,1
deci y = 8,1 cm
c)BC²=CD×AC
12²=9×AC
AC=12² ÷9
AC=144 ÷9
AC=16
deci z = 16 cm
