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f(x)'=3sinx-4cosx+2tgx-5ctgx

Răspuns :

sinx derivat=cosx
cosx derivat = - sinx
tgx derivat=[tex] \frac{1}{cos ^{2}x } [/tex]
ctgx derivat=[tex] \frac{-1}{sin ^{2}x } [/tex]

=3cosx+4sinx+[tex] \frac{2}{cos ^{2}x } [/tex]+[tex] \frac{5}{sin ^{2}x } [/tex]
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