V = l³ = 2³ = 8 cm³
d = l√3 = 2√3 cm
At = 6Ab
Ab = l² = 2² = 4 cm²
At = 6 · 4 = 24 cm²
A doua problema
ABCDA'B'C'D' prisma triunghiulara
Fetele patrat ==> AB = BB' = B'A' = AA' = √2 cm
Al = Pb · h
Pb = 3l = 3AB = 3 · √2 = 3√2 cm
Al = 3√2 · √2 = 3·2 = 6 cm²
V = Ab · h
Ab = [tex] \frac{ l^{2} \sqrt{3} }{4} = \frac{ AB^{2} \sqrt{3} }{4} = \frac{ \sqrt{2} ^{2} \sqrt{3} }{4} = \frac{2 \sqrt{3} }{4} = \frac{ \sqrt{3} }{2} [/tex]
V = [tex] \frac{ \sqrt{3} }{2} [/tex] · √2 = [tex] \frac{ \sqrt{6} }{2} [/tex]
