5)a+a+2+a+4+a+6=404
4a+12=404
4a=404-12
4a=392
a=392:4
a=98 (I nr)
98+2=100 (II nr)
98+4=102 (III nr)
98+6=104(IV nr)
6)metoda grafica:
I------I+36I ⇒bile galbene
I------I ⇒bile rosii
I------I------I------I ⇒bile negre
Suma=481
481-36=445
445:5=89 bile rosii
89+36=125 bile galbene
89x3=267 bile negre
metoda algebrica:
a+b+c=481
a=b+36
c=3b
b+36+3b+b=481
5b+36=481
5b=481-36
5b=445
b=445:5
b=89 bile rosi
a=89+36
a=125 bile galbene
c=89x3
c=267 bile negre