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Stiind ca trei copii au impreuna 100 lei, primii doi au 56 lei, iar ultimii doi au 77 lei, afla cati lei are fiecare.

Răspuns :

Algebric:
Notam copiii cu a,b si c
a+b+c=100
a+b=56
b+c=77
Inlocuim:
a+77=100
a=23
b=56-23=33
c=77-33=44

Grafic:
|-a-|---b---|-----c-----| = 100
|-a-|---b---| =56
|---b---|-----c-----|=77
56+|-----c-----|=100 
|-----c-----|=100-56
|-----c-----|=44
|---b---|=77-44=33
|-a-|=56-33=23


a+b+c=100
a+b=56
b+c=77
a=100-77 a=23
b=56-23 b=33
c=77-33 c=44
Verificare:
23+33+44=100
23+33=56
33+44=77
Raspuns: a=23;
b=33;
c=44.