avem numerele ... a ; b si c !
a : b = 3 (rest 2) => a = 3b+2
a : c = 2 (rest 3) => a = 2c+3 sau c = (a-3)/2
a + c = 24 => 3b+2 + (a-3)/2 = 24 | *2
6b+4 + a -3 = 48 <=> 6b+4 + 3b+2-3 = 48
deci 9b=48-3 adica b = 5 ;
=> a=3*5+2=17 si c= (17-3)/2=7 ;
R: a=17 ; b=5 si c=7 .