Notam :
w,x,y,z-nr. necunoscute,unde w-mama x-tata y-fiul z-fiica.
w=x-5 ==>x=w+5
w=2y+2 ==>y=(w-2)/2
z=w/2.
Ecuatia devine: w+w+5+(w-2)/2 + w/2=184.
2w+5+w-1=184(am calculat direct fractiile si am
simplificat cu numitorul,poti face asta singur)
3w+4=184
3w=180
w=180/3=60.
x=60+5=65
y=(60-2)2=58/2=29
z=w/2=60/2=30.
Un sfat! Fa-ti temele singur!