v1
1) logaritmezi cu log din 3 =>x/x+8=-x-3
x=(-x-3)(x+8)
x=-x^2-8x-3x-24
x^2+12x+24=0
calculezi Δ....
2)x+1+x+2=2
2x+3=2
2x=-1
x=-1/2
3)3-x+1-x=2^3
4-2x=8
-2x=4
x=-2
4)2x-5+2x-1=5
4x-6=5
4x=11
x=11/4
V2
1)㏒2(x)+log8(x)=8
log2(x)+1/3log2(x)=2^8
notam log2(X)=a
a+a/3-256=0
3a-a=256
2a=256=>a=128
log2(x)=2^7=>x=7
