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Δdreptunghic ABC are ipotenuza=24 si masura ∡B=60°. calculate AC,AB SI AD(INALTIMEA)

Răspuns :

B=60° C=30° => AB=BC/2 = 24/2 = 12cm TP =>AC²=BC²-AB² AC²=24²-12² AC²=576-144 AC=√432 AC=12√3 T.CATETEI=>AB²=BD×BC 12²=BD×24 BD=144/24 BD=6 CD=BC-BD CD=24-6 CD=18 T.ÎNĂLŢIMII=>AD²=BD×CD AD²=6×18 AD²=102 AD=√108 AD=6√3