-calculez masa si molii de KOH din solutia data
c/100= md/ms; 10/100=md/224---> md= 22,4g
n= m/M; n= 22,4g/(39gK+1gH+ 16gO)/mol= 0,4molKOH
-ECUATIA REACTIEI
2mol 1mol
2KOH + H2SO4----> K2SO4+2H2O
0,4mol.........n= 0,2mol
-calculez volumul solutiei de acid
c= n/V; 0,002= 0,2/ V---------------> rezulta V in litri, transforma-l in ml !