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Sa se rezolve inecuatiile: -1<2x-3 supra x-5<3
-2 Dau coroana!!!!


Răspuns :

1)[tex]0 \leq 1+ \frac{2x-3}{x-5} \\ \frac{2x-3}{x-5} -3\ \textless \ 0 \\ 0 \leq \frac{x-5+3x-3}{x-5} \\ \\ 0 \leq \frac{4x-8}{x-5} \\ x=5 \\ x=2 \\ \\ - \\ x ----2--5 \\ 4x-8 --+++ \\ x-5-----+++ \\ ++++++--+++ \\ xapartine(2,5) \\ \frac{2x-3-3x+15}{x-5} \ \textless \ 0 \\ \frac{-x+12}{x-5} \ \textless \ 0 \\ x=12 \\ x=5faci tabel corect \\ \\ x------5-------12 \\ -x+12+++++++++++---- \\ x-5----+++++++++ \\ -------+++++++ [/tex]
x apartine(-oo  5)care intersectat cu x(2,5)
x apartine(2,5)