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Rezolvati in R ecuatia :b)3x²+4x-4=0

Răspuns :

3x^2+4x-4=0
∆=b^2-4ac
∆=4^2-4•3•(-4)
∆=16+48=64
√∆=√64=8
x1=(-b-√∆)/2a
x1=(-4-8)/2•3=-12/6=-2
x2=(-b+√∆)/2a
x2=(-4+8)/2•3=4/6=2/3