ecuatia reactiei:
C6H6 +HONO2--->C6H5-NO2+ H2O
M, C6H6= (6X12gC+6gH)/mol= 78g/mol
M, HNO3= (1gH+ 14gN+3X16gO)/mol= 63g/mol
M, nitrobenzen=(6x12gC+5gH+14gN+32gO)/mol= 123g/mol
revin la ecuatie
1mol benzen.........1mol acid azotic.......1 mol nitrobenzen
78g............................63g..............................123g
100.....................................x....................................y
calculeaza x si y
