piramida patrulatera regulata(baza patrat)
diagonala bazei=6√2=l√2 => l=6 cm (l=latura bazei)
ap(apotema piramidei)=3√2
Volumul piramidei = (Ab·h)/3
Ab=l²=6²=36 cm²
ab(apotema bazei)=l/2=6/2=3 cm
h=inaltimea piramidei
h²=ap²-ab²
h²=(3√2)²-3²
h²=18-9
h²=9 => h=√9 => h=3 cm
V=(Ab·h)/3 = (36·3)/3=36 cm³
