[tex]\displaystyle \\
\texttt{Simplificam fortat fractia } ~ \frac{2a-b}{3b} ~~\texttt{cu a.} \\ \\
\frac{2a-b}{3b}^{(a} = \frac{\frac{2a}{a}-\frac{b}{a}}{\frac{3b}{a}}= \frac{2-\frac{1}{2}}{\frac{3}{2}}=\frac{\frac{3}{2}}{\frac{3}{2}}= \boxed{1}[/tex]
