[tex]tgB=\dfrac{AC}{AB}\Rightarrow \dfrac34=\dfrac{AC}{24}\Rightarrow AC=\dfrac{24\cdot3}{4}=18\ cm[/tex]
Cu teorema lui Pitagora avem:
[tex]BC^2=AB^2+AC^2=24^2+18^2=576+324=900\Rightarrow [/tex]
[tex]\Rightarrow BC=30\ cm.[/tex]
[tex]A_{ABC}=\dfrac{18\cdot24}{2}=216\ cm^2.\ \ P_{ABC}=18+24+30=...[/tex]