aria ferestrei Af
Af = aria ABCD + aria semicercului = ABxBC + π R^2 /2
Af = 1 x 1,2 +π/8
Af = 1,2 + 0,125π
b) aria CMDP = aria tr DCM + aria tr DPC = DC x CB/2 + DC x R/2
aria CMDP = 1 x 1,2/2 + 1 x 0,5/2 = 0,85 = 17/20
c) lungime profil Lp
Lp = πR + 2 x AB + 3 x BC = 0,5π + 5,6 = (5π + 56)/10
daca se considera 3,14 < π < 3,15 luam π max
Lp = (5 x 3,15 + 56)/10 = 7,175m
deci 7,2 m de profil sunt suficienti
