ducem DE_I_AB si CF_I_AB
notam AE=x si FB=y
aplicam teorema lui Pitagora
DE=CF
DE²=25²-x²=625-x²
CF²=17²-y²=289-y²
625-x²=289-y² x²-y²=625-289 (x+y)(x-y)=336
x+y=32-4=28
x-y=336:28=12
2x=28+12
2x=40
x=20 cm
y=28-20=8 cm
DE=CF=√(625-400)=√225=15
AF=4+20=24 cm
AC=√24²+15²=√576+225=√801=3√89 cm
EB=4+8=12 cm
DB=√12²+15²=√144+225=√369=3√41 cm
