Aplici T. < de 30 de grade in triunghiul dreptunghic ABC:
AC = BC/2 => BC = 2AC;
De asemenea, aplici T. Pitagora si obtii ca (2AC)^2 = 324 + AC^2 =>
3AC^2 = 324 => AC ^2 = 108 => AC = 6[tex] \sqrt{3} cm;[/tex] => BC = 12[tex] \sqrt{3} cm[/tex];
In final P Δ ABC = 18( 1 + [tex] \sqrt{3} ) cm;[/tex]
Bafta!