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Rezolvati urmatoarele ecuatii:
8x+2,6=7x+3,18
6z-4=3z+3,11
5x-1,26=3x+7,47
3•(1,7x+5,7)+1,8=3,2x+22,7
5x-18,5+3x=1-0,25x
0,2(3x-5,5)+7,3x=5(x+0,8)
(2,3+x)•0,5-0,3=1-0,25x
x•0,75+0,3•(0,5x+1,25)=1,59+1,2 la puterea 2.
Varog urgent dau 100 puncte


Răspuns :

ex.1 
8x+2,6=7x=3,18
8x-7x+26-318=0
x-292=0
x=292⇒Verificare:
x-292=0
x=292⇒292-292=0
0=0 (Adev.)

ex.2
6z-4=3z+3,11
6z-4=3z+311
6z-3z-4-311=0
3z-315=0
3z=315
z=[tex] \frac{315}{3} [/tex]
z=105
⇒Verificare: 3z-315=0
3×105-315=0
315-315=0
0=0 (Adev.)

Pentru cateva nr de acolo ai exemplu
1,26=[tex] \frac{1,26}{100} [/tex]
⇒126

0,8=[tex] \frac{0.8}{10} [/tex]
⇒8

0,75=[tex] \frac{0,75}{100} [/tex]
⇒75

Succes