Masa moleculara a NaOH = 23 +16 +1=40
Consideram 40 ……………………..100%
23 ……………………….x%
16………………………y%
1………………………..z%
De aici scoatem fiecare necunosctuta
astfel:
X=23*100/40=57,5% Na
Y=16*100/40=40%O
Z=1*100/40=2,5%H
La fel facem si pt Ca(OH)2
Masa molecular: 23+2*(16+1)=57
57…………………………….100%
23……………………………..x%
2*16…………………………y%
2*1……………………………z%
X=(23*100)/57=40,35 % Ca
Y=(2*16*100)/57=56,14%O
Z=(2*1*100/57)=3,50%H
Masa molecular KOH= 39+16+1=56
56………………………………100%
39………………………………..x%
16……………………………… y%
1…………………………………. Z%
X=(39*100)/56=69,64%
Y=(16*100)/56=28,57%
Z=(1*100)/56=1,78%
