1. nr moli=m/M=490/98=5 moli
MH2So4=98g/mol
2.CaSo4 raport între cine ?
3.Ca3(Po4)2 si HNO3
MCa3(PO4)2=40*3+2(31+64)=120+190=310g/mol
MHNO3=63g/mol
MCa3(PO4)2/MHNO3=310/63
4.MNH3=14+3*1=17g/mol
%N=mN/M*100=14/17*100=82.34%
%H=mH/M*100=3/17*100=17.64%
MCH4=12+4*1=16g/mol
%C=mC/M*100=12/16*100=75%
H=25%
MAl2(SO4)3=27*2+3(32+64)=54+288=342g/mol
%Al=mAl/M*100=54/342*100=15.78%
%S=mS/M*100=96/342*100=28%
%O=mO/M*100=192/342*100=56.14%
5. MH2CO3=2*1+12+48=62g/mol
mO=48g
MBa(OH)2=137+2(16+1)=137+34=171g/mol
mO=32g
MCaO=40+16=56g/mol
mO=16g